A little tip for everyone doing the split mono while using a pedal with it's own fx return...
TLDR: Treat the input/send on the pedal as "pedal A", and the return/output on the pedal as "Pedal B"
Here's the long version:
- Each loop can be split into 2 mono loops using TRS insert cables:
- - - Send Loop 1: Tip goes to the Input of the pedal you want in Loop 1, Ring goes to the input of the pedal you want in Loop 7
- - - Return Loop 1: Tip goes to the Output of the pedal you want in Loop 1, Ring goes to the Output of the pedal you want in Loop 7
So Loop 1, both the input and output should be connected to the TIP of Loop 1's send and returns, while Loop 7 is connected to the RING of Loop 1's send and returns.
Pretty straightforward, and I got all my patches correct on first time. Then I hit a snafu when wiring in a pedal that has it's own fx loop, the 3Leaf Audio Chromatron.
I wanted the input/send of the chromatron to be connected to loop 2 (need my impedance sensitive fuzz first), and the return/output of the chromatron on Loop 8. This way, I can have my overdrives, modulation, and PLL within the fx loop of my chromatron (and thus trigger the envelope detector of the chromatron from my clean signal with the most dynamics, but apply the filter after said pedals).
Where I confused myself was in wiring the Input/Send using the Tip and Ring of Loop 2, instead of the Tip and Tip. The Input/Send is essentially "pedal A" which should be Loop 2, and the Return/Output should be "pedal B" which should be loop 8. I spent about an hour troubleshooting (first checked my programming on the MEGX and GT-22, then changed cables and slots on the MEGX, then pulled out the chromatron to test if it worked properly outside of the MEGX, before I realized I wired it wrong).
So it should've been wired like this:
- - - Send Loop 2: Tip goes to the Input of the Chromatron (aka the input of Pedal A), Ring goes to the Return of the Chromatron (aka the input of Pedal B)
- - - Return Loop 2: Tip goes to the Send of the Chromatron (aka the output of Pedal A), Ring goes to the Output of the Chromatron (aka the output of Pedal B).
Anyways, that was the only brain-twister I got from wiring it. It's actually straightforward, but figured someone might also get snagged on this down the line, so I thought it would be helpful.